(f^2+5f-12)/(f-3)=

Solution for (f^2+5f-12)/(f-3)= equation:

(f^2+5f-12)/(f-3)=

We move all terms to the left:

(f^2+5f-12)/(f-3)-()=0


Domain of the equation: (f-3)!=0

We move all terms containing f to the left, all other terms to the right

f!=3

f∈R


We add all the numbers together, and all the variables

(f^2+5f-12)/(f-3)=0

We multiply all the terms by the denominator


(f^2+5f-12)=0

We get rid of parentheses

f^2+5f-12=0

a = 1; b = 5; c = -12;
Δ = b2-4ac
Δ = 52-4·1·(-12)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{73}}{2*1}=\frac{-5-\sqrt{73}}{2}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{73}}{2*1}=\frac{-5+\sqrt{73}}{2}
$